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sakuraharuno1234
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Nguyễn Hoàng Minh
5 tháng 11 2021 lúc 14:26

\(=\dfrac{11}{17}:\dfrac{19}{40}+\dfrac{11}{17}:\dfrac{23}{20}=\dfrac{11}{17}\cdot\left(\dfrac{40}{19}+\dfrac{20}{23}\right)=\dfrac{11}{17}\cdot\dfrac{1300}{437}=\dfrac{14300}{7429}\)

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Di Di
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Ngọc
25 tháng 3 2018 lúc 10:27
1/7-8/7:5:3/4(-2) mũ 2 1/7-8/7:23/4*(-4) 1/7-8/7..k bik lm nx
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Đoàn Nguyễn Bảo Long
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Thanh Hoàng Thanh
19 tháng 1 2022 lúc 15:23

\(\left(1\right)\dfrac{-7}{12}.\dfrac{11}{8}-\dfrac{37}{8}.\dfrac{7}{12}+\dfrac{1}{2}=-\dfrac{7}{12}.\left(\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=-\dfrac{7}{12}.6+\dfrac{1}{2}=-3.\)

\(\left(2\right)\left(\dfrac{2}{3}-\dfrac{1}{4}-\dfrac{5}{6}\right).\left(-2\right)^2+\dfrac{3}{2}:\dfrac{-15}{4}=\dfrac{-5}{12}.4-\dfrac{2}{5}=\dfrac{-5}{3}-\dfrac{2}{5}=\dfrac{-31}{15}.\)

\(\left(3\right)\dfrac{-2}{5}+\dfrac{3}{10}-\dfrac{3}{5}+\dfrac{7}{10}-\dfrac{3}{2}=1-1-\dfrac{3}{2}=-\dfrac{3}{2}.\)

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Trường Nguyễn Công
19 tháng 1 2022 lúc 15:37

1. \(\dfrac{-7}{12}.\dfrac{11}{8}-\dfrac{37}{8}.\dfrac{7}{12}+\dfrac{1}{2}=\dfrac{-7}{12}\left(\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=\dfrac{-7}{12}.\dfrac{6}{1}+\dfrac{1}{2}=\dfrac{-7}{2}+\dfrac{1}{2}=\dfrac{-6}{2}=-3\)2.
\(\left(\dfrac{2}{3}-\dfrac{1}{4}-\dfrac{5}{6}\right).\left(-2\right)^2+\dfrac{3}{2}:\dfrac{-15}{4}=\dfrac{-5}{12}.4+\dfrac{-2}{5}=\dfrac{-5}{3}+\dfrac{-2}{5}=\dfrac{-31}{15}\)
3.
\(\dfrac{-2}{5}+\dfrac{3}{10}-\dfrac{3}{5}+\dfrac{7}{10}-\dfrac{3}{2}=\dfrac{-4}{10}+\dfrac{3}{10}-\dfrac{6}{10}+\dfrac{7}{10}-\dfrac{15}{10}=\dfrac{-15}{10}=\dfrac{-3}{2}\)

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Đoàn Nguyễn Bảo Long
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Thanh Hoàng Thanh
19 tháng 1 2022 lúc 15:17

\(\dfrac{-7}{12}.\dfrac{11}{8}-\dfrac{37}{8}.\dfrac{7}{12}+\dfrac{1}{2}=\dfrac{-7}{12}.\left(\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=-\dfrac{7}{12}.6+\dfrac{1}{2}=-\dfrac{7}{2}+\dfrac{1}{2}=-3.\)

\(\left(\dfrac{2}{3}-\dfrac{1}{4}-\dfrac{5}{6}\right).\left(-2\right)^2+\dfrac{3}{2}:\dfrac{-15}{4}=\dfrac{8-3-10}{12}.4+\dfrac{-2}{5}=\dfrac{-5}{12}.4-\dfrac{2}{5}=\dfrac{-5}{3}-\dfrac{2}{5}=-\dfrac{31}{15}.\)

\(\dfrac{-2}{5}+\dfrac{3}{10}-\dfrac{3}{5}+\dfrac{7}{10}-\dfrac{3}{2}=\left(\dfrac{3}{10}+\dfrac{7}{10}\right)+\left(\dfrac{-2}{5}-\dfrac{3}{5}\right)-\dfrac{3}{2}=1-1-\dfrac{3}{2}=\dfrac{-3}{2}.\)

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Đoàn Nguyễn Bảo Long
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Nguyễn Lê Phước Thịnh
19 tháng 1 2022 lúc 23:19

1: \(=\dfrac{7}{12}\left(-\dfrac{11}{8}+\dfrac{37}{8}\right)+\dfrac{1}{2}=\dfrac{7}{12}\cdot\dfrac{26}{8}+\dfrac{1}{2}=\dfrac{115}{48}\)

2: \(=\dfrac{8-3-10}{12}\cdot4+\dfrac{3}{2}\cdot\dfrac{-4}{15}\)

\(=\dfrac{-5}{3}+\dfrac{-12}{30}=\dfrac{-5}{3}+\dfrac{-2}{5}=\dfrac{-25-6}{15}=-\dfrac{31}{15}\)

3: \(=\dfrac{-2}{5}-\dfrac{3}{5}+\dfrac{3}{10}+\dfrac{7}{10}-\dfrac{3}{2}=-\dfrac{3}{2}\)

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nguyễn thị quỳnh như
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Kẻ Bí Mật
23 tháng 4 2015 lúc 13:40

a) 20

b) 2

c) 0

d) -1

Like  nha bạn !!

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Nguyễn Hữu Đồng
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Phạm Quang Lộc
28 tháng 7 2023 lúc 21:08

\(\dfrac{11}{6}+\dfrac{1}{4}=\dfrac{22}{12}+\dfrac{3}{12}=\dfrac{25}{12}\)

\(\dfrac{2}{5}-\dfrac{3}{8}=\dfrac{16}{40}-\dfrac{15}{40}=\dfrac{1}{40}\)

\(\dfrac{3}{10}-\dfrac{4}{15}=\dfrac{9}{30}-\dfrac{8}{30}=\dfrac{1}{30}\)

\(3+\dfrac{2}{5}=\dfrac{15}{5}+\dfrac{2}{5}=\dfrac{17}{5}\)

\(\dfrac{333}{777}+\dfrac{22}{55}=\dfrac{3}{7}+\dfrac{2}{5}=\dfrac{15}{35}+\dfrac{14}{35}=\dfrac{29}{35}\)

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Quynh Anh
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Thảo Nguyễn『緑』
3 tháng 5 2019 lúc 18:44

\(\left(-\frac{1}{2}\right)^2\cdot2\cdot\frac{7}{4}\div\left(\frac{5}{8}-1\frac{3}{16}\right)\)

\(=\frac{1}{4}\cdot2\cdot\frac{7}{4}\div\left(\frac{10}{16}-\frac{19}{16}\right)\)

\(=\frac{7}{8}\div\left(-\frac{9}{10}\right)\)

\(=\frac{7}{8}\cdot\left(-\frac{10}{9}\right)\)

\(=-\frac{35}{36}\)

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hoàng anh vũ
3 tháng 5 2019 lúc 18:47

-1/2^2.7/4:(5/8-1 3/16)=1/4.7/4:(5/8-19/16)=1/4.7/4:(10/16-19/16)=1/4.7/4:-9/16=1/4.7/4.-16/9=1/4.-28/9=-7/9

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Thảo Nguyễn『緑』
3 tháng 5 2019 lúc 18:50

\(17\frac{6}{11}\cdot\frac{4}{27}-8\frac{6}{11}\div\frac{27}{4}+350\%\)

\(=17\frac{6}{11}\cdot\frac{4}{27}-8\frac{6}{11}\cdot\frac{4}{27}+\frac{7}{2}\)

\(=\frac{4}{27}\cdot\left(17\frac{6}{11}-8\frac{6}{11}\right)+\frac{7}{2}\)

\(=\frac{4}{27}\cdot9+\frac{7}{2}\)

\(=\frac{4}{3}+\frac{7}{2}\)

\(=\frac{29}{6}\)

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Trần Thái Khang
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